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0=-4.9x^2+10x+600
We move all terms to the left:
0-(-4.9x^2+10x+600)=0
We add all the numbers together, and all the variables
-(-4.9x^2+10x+600)=0
We get rid of parentheses
4.9x^2-10x-600=0
a = 4.9; b = -10; c = -600;
Δ = b2-4ac
Δ = -102-4·4.9·(-600)
Δ = 11860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11860}=\sqrt{4*2965}=\sqrt{4}*\sqrt{2965}=2\sqrt{2965}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{2965}}{2*4.9}=\frac{10-2\sqrt{2965}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{2965}}{2*4.9}=\frac{10+2\sqrt{2965}}{9.8} $
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